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0.06d^2-0.6d-3=0
a = 0.06; b = -0.6; c = -3;
Δ = b2-4ac
Δ = -0.62-4·0.06·(-3)
Δ = 1.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{1.08}}{2*0.06}=\frac{0.6-\sqrt{1.08}}{0.12} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{1.08}}{2*0.06}=\frac{0.6+\sqrt{1.08}}{0.12} $
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